2 coins and 1 six sided cube are tossed. What is the probability of getting two heads and and a four?

minus 2 from 6 and get a four i think

i do not understand what you are saying...i need to find the probability of getting 2heads combined with rolling a four on a number cube

The probability of a head on each toss = .5 or 1/2.

The probability of getting a 4 is 1/6.

The probability of all the events occurring is found by multiplying the probability of the individual events — 2 coin tosses and one roll of the die.

I hope this helps. Thanks for asking.

To find the probability of getting two heads and a four, we need to determine the total number of possible outcomes and the number of favorable outcomes.

First, let's consider the coins. Since we have 2 coins, each coin can have 2 possible outcomes (heads or tails). Therefore, there are 2 * 2 = 4 possible outcomes for the coins.

Next, let's consider the cube. As it is a standard six-sided cube, it can have 6 possible outcomes (numbers 1 to 6).

To find the total number of outcomes for both the coins and the cube, we multiply the number of outcomes for each. Thus, the total number of possible outcomes is 4 * 6 = 24.

Now let's determine the number of favorable outcomes, which is the outcome we are interested in (two heads and a four).

For the coins, the favorable outcome is having both coins showing heads, which has only 1 outcome.

For the cube, the favorable outcome is rolling a four, which again has only 1 outcome.

To find the total number of favorable outcomes, we multiply the number of outcomes for each. So, the total number of favorable outcomes is 1 * 1 = 1.

Therefore, the probability of getting two heads and a four is the number of favorable outcomes divided by the number of possible outcomes: 1/24.

Hence, the probability of getting two heads and a four is 1/24.