# Algebra

Consider the line with equation
5x – 2y = 10.

(a) Find the y-intercept for the given line.

(b) Find the slope for a line parallel to the given line.

(c) Find the slope for a line perpendicular to the given line.

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1. (a) Find the y-intercept for the given line.

(b)Find the slope for a line parallel to the given line.

(c) Find the slope for a line perpendicular to the given line.

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2. y intercept is when x = 0
-2y = 10
y = -5

2 y = 5 x - 10
y = (5/2) x = 5
so m, the slope, = (5/2)

m'= -1/m
m' = -2/5

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3. This is interesting, I got the first one correct for y = -5 because x = 0 but still do not get how you come up with 5/2 for the slope of the parallel line and the slope of the perpendicular one either? Can you please explain. Thanks!

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4. how did you come up with (5/2)

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