I have the same question as Sally:
What is the prime factorization of 225?
Or, just how do you find prime factorization???
Thanks.
I stary with an obvious prime
225 = 5 * 45, now another 5
= 5*5*9
= 5*5*3*3
okay, so if you had to find it of 500, it would be:
500=5*100
5*10*10
5*5*2*5*2
the soltion would be
5^3*2^2
did I do this right?
Oh, it was me who posted the last post as anonymous, i forgot to put my name in!
yes
thank you so much
For the prime factor of 255= 3*3*5*5
To find the prime factorization of a number, such as 225, you need to determine which prime numbers multiply together to give the original number. Prime factorization is the process of breaking down a composite number into its prime factors.
To find the prime factorization of 225, you can start by dividing it by the smallest prime number, which is 2. If it is divisible, divide it repeatedly until it is no longer divisible. In this case, 225 is odd, so it is not divisible by 2.
Next, move on to the next prime number, which is 3. Divide the number by 3 and continue dividing until it is no longer divisible. In this case, 225 divided by 3 is 75. Continue dividing 75 by 3 until you can't divide it anymore. When you divide 75 by 3, you get 25. Then, you divide 25 by 3 and get 8.33, which is not a whole number. So, we stop here.
Now, it's time to move on to the next prime number, which is 5. Divide the current quotient (which is 25) by 5 until it is no longer divisible. When you divide 25 by 5, you get 5.
After this step, you have reached the end because you can no longer divide 5 by any more prime numbers. So, the prime factorization of 225 is 3 x 3 x 5 x 5, or written more commonly as 3^2 x 5^2.
In summary, to find the prime factorization of a number, divide it by the smallest prime numbers starting from 2 and continue dividing until the quotient is no longer divisible by that prime number. Repeat this process with the next prime numbers until you can no longer divide the quotient by any prime numbers. The prime factors you obtained are then multiplied together to get the prime factorization of the original number.