Given that f(x)= 2x-5 and g(x) =x^2-31, calculate the value of
1)f(-2)= 2(-2)-5 = -1 is this correct?
2) gf(1)= 1-31 = -30 is this correct?
3)f indirect 1(3) how do i do this one?
1) f(-2) = 2(-2) - 5
= -4 - 5
= -9
2) you found g(1)
if by gf(1) you mean g(f(1))
then
g(f(1)) = g(2-5))
= g(-3)
= (-3)^2 - 31
= 9 - 31
= -22
3) I don't a clue what you mean by
"f indirect 1(3)"
I have never seen that notation.
How do I work ok x square 2
To find f indirect 1(3), we first need to substitute 3 into the function f(x) = 2x-5.
So, f indirect 1(3) means we substitute 3 into f(x) as if we were finding f(3).
f(3) = 2(3) - 5
= 6 - 5
= 1
Therefore, f indirect 1(3) = 1.
To solve the problem 3), you are asked to find the composition of two functions, f and g, applied to x = 3.
The composition of two functions, f and g, denoted as (g ∘ f)(x), is calculated by first applying f to x and then applying g to the result.
To find f indirect 1(3), follow these steps:
1. Substitute x = 3 into the function f.
f(3) = 2(3) - 5 = 6 - 5 = 1
2. Now take the result from f(3) and insert it into the function g.
g(1) = 1^2 - 31 = 1 - 31 = -30
Therefore, f indirect 1(3) = -30.
Feel free to ask if you have any further questions!