Let g(x) = 10-x/2+x

a. Find g(-1)

b. state the domain of the function
10-x/2+x

c. Find g (t + 1) and simplify as much as possible

were do you get t from there is no t in the equation?

I answered this question a few days ago. You need to use parentheses to clarify what the function is. Are you the person who asked it before?

g(- 1) = 10 - (-1)/2 + - 1 = 19/2 nineteen over two

b. all reals

c. 21 + t
I think this is correct, I am rusty.

Thanks for all your help, but I still do not understand how you come up with the answers you do. This is what I got

(a) Find g (¨C1).

(gx)= (10-x) / (2+x)

then g (-1) = (10-(-1))/ (2+ (-1))
= 11/1 = 11

(b)The domain is the set of all real numbers except x=-2

Domain = {x ©¦ x (the 'is an element' symbol) R, x ¡Ù -2}

(c) Find g (t + 1) and simplify as much as possible. Show work.

g (t+1)

= (10 - (t+1))/ (2+ (t+1))
= (9-t)/ (3+t)

Are any of these correct? Thanks!

The symbols are not displaying correctly. So here is what I got once again.

(a) Find g (–1).

(gx)= (10-x) / (2+x)

then g (-1) = (10-(-1))/ (2+ (-1))
= 11/1 = 11

b. The domain is the set of all real numbers except x=-2

(c) Find g (t + 1) and simplify as much as possible. Show work.

g (t+1)

= (10 - (t+1))/ (2+ (t+1))
= (9-t)/ (3+t)

Are these correct? Thanks!

a. To find g(-1), you need to substitute -1 for x in the function g(x).

So, substitute -1 for x in g(x):

g(-1) = 10 - (-1)/2 + (-1)

Now simplify:

g(-1) = 10 + 1/2 - 1

Adding the fractions, we get:

g(-1) = 10 + 1/2 - 2/2

Combining the terms, we have:

g(-1) = 10 - 1/2

b. To state the domain of the function g(x) = 10 - x/2 + x, we need to determine all the possible values that x can take.

In this case, since there are no restrictions or limitations in the function, the domain is all real numbers. So the domain of the function is (-∞, +∞).

c. To find g(t + 1) and simplify as much as possible, you need to substitute (t + 1) for x in the function g(x).

So, substitute (t + 1) for x in g(x):

g(t + 1) = 10 - (t + 1)/2 + (t + 1)

Now simplify:

g(t + 1) = 10 - t/2 - 1/2 + t + 1

Combining like terms:

g(t + 1) = (10 + 1) + (t - t)/2 + 1/2

Simplifying further:

g(t + 1) = 11 + 0/2 + 1/2

Finally, we have:

g(t + 1) = 11 + 1/2

So, g(t + 1) simplifies to 11 + 1/2.