In outer space, a constat net force of magnitude 140 N is exerted on a 32.5 kg probe initially at rest. (a) what acceleration does thie force produce? (b) how far does the probe travel in 10.0 s...
I got a which equals 4.31 m.s^2 but how do i solve for b
Use
S=ut+0.5at2
S=distance travelled
u=initial velocity (=0)
t=10 s.
a=4.31 m/s/s
g is not involved because it is in outer space.
where did you get the 0.5 ??
actually the formula says
S=ut+at2/2
(ut plus half at2)
I now realize that the 0.5 is confusing.
and i did 0(10) + 0.5(4.31 m/s/s)(10)^2= 225.5 and that is not right because the answer is 215
You may have put in the wrong number on the calculator, because 431/2=215.5 ≈ 215
WTF man
To solve for part (b), you can use the kinematic equation:
\[d = v_0t + \frac{1}{2}at^2\]
where:
- d is the distance traveled by the probe (which we want to find),
- \(v_0\) is the initial velocity (which is zero because the probe starts from rest),
- t is the time (given as 10.0 s),
- a is the acceleration (which you correctly found to be 4.31 m/s²).
Plugging in the values we know:
\[d = 0 \cdot 10 + \frac{1}{2}(4.31)(10)^2\]
Simplifying this equation:
\[d = 0 + \frac{1}{2}(4.31)(100)\]
\[d = 215.5\]
Therefore, the probe travels a distance of 215.5 meters in 10.0 seconds.