Algebra

Find the axis of symmetry

y=x^2-7x+2

Well, it's a parabola. If you rewrite the equation by completing the square, you get

y = (x - 7/2)^2 + 2 - (7/2)^2
= (x - 7/2)^2 - 41/4

It will be symmetric about the x = 7/2 line and the minimum will be at y = -41/4.

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