Find the axis of symmetry
y=x^2-7x+2
Well, it's a parabola. If you rewrite the equation by completing the square, you get
y = (x - 7/2)^2 + 2 - (7/2)^2
= (x - 7/2)^2 - 41/4
It will be symmetric about the x = 7/2 line and the minimum will be at y = -41/4.
To find the axis of symmetry of a quadratic equation in the form y = ax^2 + bx + c, you can use the formula x = -b/2a. In this case, the equation is y = x^2 - 7x + 2.
To find the axis of symmetry, you need to determine the values of a, b, and c in the equation.
In this case, a = 1, b = -7, and c = 2.
Using the formula, we can substitute the values into x = -b/2a:
x = -(-7) / 2(1)
x = 7/2
Therefore, the axis of symmetry is x = 7/2.