Can u please give me a balanced eqn. for the reaction of Malonic acid with KOH
Malonic acid is HOOC-CH2-COOH
Acid + base ==> salt + water.
HOOCCH2COOH + 2KOH ==> KOOCCH2COOK + 2H2O
The balanced equation for the reaction of Malonic acid (HOOCCH2COOH) with KOH (potassium hydroxide) can be obtained by following a few steps:
1. Identify the reactants and products: The reactants are Malonic acid (HOOCCH2COOH) and KOH (potassium hydroxide). The products are the salt formed (KOOCCH2COOK) and water (H2O).
2. Write the skeleton equation: Write the reactants on the left side of the equation and the products on the right side. The skeleton equation is: HOOCCH2COOH + KOH ---> KOOCCH2COOK + H2O.
3. Balance the atoms other than hydrogen and oxygen: We can see that there are 2 carbon atoms, 4 hydrogen atoms, and 3 oxygen atoms on each side of the equation. These atoms need to be balanced by adjusting the coefficients.
4. Start with the carbon atoms: There are 2 carbon atoms on the left side and 3 carbon atoms on the right side. To balance them, we can put a coefficient of 3 in front of the Malonic acid on the left side: 3HOOCCH2COOH + KOH ---> KOOCCH2COOK + H2O.
5. Balance the oxygen atoms: There are 6 oxygen atoms on the left side and 3 oxygen atoms on the right side. To balance them, we can put a coefficient of 3/2 in front of water on the right side: 3HOOCCH2COOH + KOH ---> KOOCCH2COOK + 3/2 H2O.
6. Balance the hydrogen atoms: There are 8 hydrogen atoms on the left side and 8 hydrogen atoms on the right side. The hydrogen atoms are already balanced.
7. Final balanced equation: After balancing all the atoms, the final balanced equation is: 3HOOCCH2COOH + KOH ---> KOOCCH2COOK + 3/2 H2O.
So, the balanced equation for the reaction of Malonic acid with KOH is 3HOOCCH2COOH + KOH --> KOOCCH2COOK + 3/2 H2O.