I need help with this problem,

(3-x)/-4 = (x+6)/3

Thanks! I've tried it myself several times and I keep getting stuck.

multiply both sides of the equation by -12

Yields

9-3x=-4x-24
add 4x to each side, subtract 9 from each side.

I don't really see how that works.

To solve the equation (3-x)/-4 = (x+6)/3, we need to eliminate the fractions and isolate the variable.

First, we can start by cross-multiplying to get rid of the fractions. This means multiplying the numerator of one fraction by the denominator of the other fraction, and vice versa. So, multiplying -4 on both sides by (3-x), and multiplying 3 on both sides by (x+6), we get:

(-4)(3-x) = (3)(x+6)

Now, we can simplify the equation:

-12 + 4x = 3x + 18

Next, we want to get all the terms containing x on one side of the equation and simplify further. This involves adding or subtracting terms to move them from one side to the other.

To do that, we can subtract 3x from both sides:

-12 + 4x - 3x = 3x - 3x + 18

This simplifies to:

-12 + x = 18

Next, we want to isolate the variable x. So, we can add 12 to both sides to move it to the right side of the equation:

-12 + x + 12 = 18 + 12

This simplifies to:

x = 30

Therefore, the solution to the equation is x = 30.

I hope this explanation helps you understand the steps involved in solving the problem!