Calculate the distance between the points -2/3 and 3/4 on the number line. Please show how you arrived at the answer.
distance=sqrt ((y1-y2)^2 + (x1-x2)^2 )
watch the signs on the negative point.
So you don't add the two to come up with the distance? All I need is the distance between the two fractions. Thanks!
take the (larger number) - (smaller number)
= 3/4 - (-2/3)
= 3/4 + 2/3
I will let you finish it.
I think bobpursley misread your question,
he gave you the formula for the distance between two points.
It will work if you consider your data to be the points (3/4,0) and (-2/3, 0)
Could you be adding both fraction here after coming up with the common denominator? which is 12?
for the final ans of 17/12 or 1 5/12?
yes
To calculate the distance between two points on the number line, you need to find the absolute value of the difference between the coordinates of the two points.
In this case, the coordinates of the two points are -2/3 and 3/4. To find the difference between these coordinates, you subtract the smaller coordinate from the larger coordinate. Since 3/4 > -2/3, we subtract -2/3 from 3/4:
3/4 - (-2/3)
To subtract fractions, you need a common denominator. The least common multiple (LCM) of 4 and 3 is 12. So you can rewrite the fractions with a common denominator of 12:
(9/12) - (-8/12)
Now you can subtract the numerators:
9/12 + 8/12 = 17/12
This gives you the difference between the two points as 17/12.
Since we are calculating the distance, we need to take the absolute value of this difference. The absolute value disregards the negative sign, giving you the distance as:
|17/12| = 17/12
Therefore, the distance between the points -2/3 and 3/4 on the number line is 17/12.