How much heat is required to raise the temperature of a 10.0 kg of aluminum by 80 degrees Celsius?
Look up the specific heat of aluminum. The units will be Calories/kg*degC or Joules/kg*degC. Multiply that number by the temperature change (80 C) and the mass (10.0 kg).
See
http://www.physicslabs.umb.edu/Physics/spring07/182_Exp_2.pdf
for additional information
Should this be the specific heat or the latent heat? I found the specific heat for aluminum is .215 cal/g and the heat of vaporization is 2500 cal/g. Are these number correct and which one do I use?
Is the formula H = mLv ???
To find the amount of heat required to raise the temperature of a substance, you need to use the specific heat. The specific heat is the amount of heat energy required to raise the temperature of one kilogram of a substance by one degree Celsius or Kelvin.
In this case, the specific heat of aluminum is given as 0.215 cal/g°C. However, it is important to convert this value to a consistent unit with the given mass of 10.0 kg. Since 1 kg is equal to 1000 g, the specific heat of aluminum can be converted to joules per kilogram per degree Celsius (J/kg°C) by multiplying it by 1000.
0.215 cal/g°C * 1000 J/cal = 215 J/kg°C
Now, you can multiply the specific heat (215 J/kg°C) by the mass (10.0 kg) and the temperature change (80 °C) to find the amount of heat required:
Heat = specific heat * mass * temperature change
Heat = 215 J/kg°C * 10.0 kg * 80 °C
By performing this calculation, you will find the amount of heat required to raise the temperature of 10.0 kg of aluminum by 80 degrees Celsius.