# jane

1. a centripetal-acceleration addict rides in uniform circular motion with period T=2s and radius r=3m. at t1 his acceleration vector= 6(m/s^2)i + -4(m/s^2)j. At that instant, what are the values of vector b (dot) vector a

and vector r (dot) vector a

All I could figure out was that through this formula: T=(2(pi))r/T
V=9.425m/s

how do you make that into a vector though? and how do you find the r vector? is there a way to find the angle theta?

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1. Vectors r, a and b have not been defined in the question. Perhaps these are notations used in your class and are obvious to you.
I suppose unit vectors i, j are parallel to the x,y-axes respectively.

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posted by MathMate
2. You have correctly calculated the tangential speed of
V=9.425m/s (=2pi*r/T)

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posted by MathMate
3. The answer is zero because the angle between the two vectors is 90. Cos(90)= 0

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posted by Scott

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