help!!need an answer
3x+4y=12 (0, ),(2/3, ),(0, ),(-2/3, )
anybody?
It looks like maybe you are supposed to take the equation 3x + 4y = 12, and solve for the values of y that correspond to given values of x. For example, when x=0, 4y = 12 and y = 3. Therefore the first "answer" is (0,3). When x = 2/3,
2 + 4y = 12 and y = 2.5
To find the value of y when x = 2/3, we substitute x = 2/3 into the equation 3x + 4y = 12:
3(2/3) + 4y = 12
2 + 4y = 12
Next, we isolate the variable y by subtracting 2 from both sides of the equation:
4y = 12 - 2
4y = 10
Now, we divide both sides of the equation by 4 to solve for y:
y = 10/4
y = 5/2
y = 2.5
Therefore, when x = 2/3, the corresponding value of y is 2.5. Thus, the second "answer" is (2/3, 2.5).
To find the values of y for the remaining values of x (0, -2/3), we can follow the same steps.
When x = 0, the equation becomes:
3(0) + 4y = 12
0 + 4y = 12
4y = 12
Then, by dividing both sides by 4:
y = 12/4
y = 3
So, when x = 0, the corresponding value of y is 3. Thus, the first "answer" is (0, 3).
Finally, when x = -2/3, the equation becomes:
3(-2/3) + 4y = 12
-2 + 4y = 12
To isolate y, we add 2 to both sides:
4y = 12 + 2
4y = 14
Dividing both sides by 4, we have:
y = 14/4
y = 7/2
y = 3.5
Therefore, when x = -2/3, the corresponding value of y is 3.5. Thus, the last "answer" is (-2/3, 3.5).
To summarize, the answers to the equation 3x + 4y = 12 for the given x-values are:
(0, 3)
(2/3, 2.5)
(0, 3)
(-2/3, 3.5)