y=5x-7 and -3x-2y=-12
I have to find the linear system using substitution
I have gotten it to -3x-2(5x-7)=-12
Now I am stuck at solving for x
PLEASE HELP any way you can
Thanks
Oh, and please show me how you did it as well
:)
where are these "200 experts"????
I thought they were on this site, ready to help us?!?!?!
keep going like you started:
-3x - 2(5x-7) = -12
expand to
-3x - 10x + 14 = -12
combine x terms
-13x +14 = -12
subtract 14 from both sides
-13x = -26
solve the above for x
thanks so much
To solve the given linear system using substitution, we need to solve one equation for one variable and then substitute that expression into the other equation.
Let's start with the first equation:
y = 5x - 7
Now, we can substitute this expression for y in the second equation:
-3x - 2y = -12
Replace y with 5x - 7:
-3x - 2(5x - 7) = -12
Expand the expression:
-3x - 10x + 14 = -12
Combine like terms:
-13x + 14 = -12
To solve for x, we need to isolate x on one side of the equation. Let's move the constant term to the other side by subtracting 14 from both sides:
-13x = -26
Now, divide both sides of the equation by -13 to solve for x:
x = -26 / -13
Simplifying, we get:
x = 2
Now that we have the value of x, we can substitute it back into either of the original equations to find the value of y. Let's use the first equation:
y = 5x - 7
Substituting x = 2:
y = 5(2) - 7
y = 10 - 7
y = 3
So, the solution to the linear system is x = 2 and y = 3.
To summarize:
x = 2
y = 3
You can check your solution by substituting these values back into the original equations to ensure they satisfy both equations.