write a balanced equation for the reaction of benzoic acid with 3 M sodium hydroxide solution
C6H5OH + NaOH ==> H2O + C6H5ONa
A typical acid + base = water + salt reaction.
To write a balanced equation for the reaction between benzoic acid (C6H5COOH) and 3 M sodium hydroxide (NaOH) solution, we first need to understand the chemical formula of these compounds and their reaction.
The chemical formula of benzoic acid is C6H5COOH, which consists of a benzene ring (C6H6) with a carboxylic acid group (-COOH) attached to it. On the other hand, the chemical formula of sodium hydroxide is NaOH, composed of a sodium ion (Na+) and a hydroxide ion (OH-).
The reaction between benzoic acid and sodium hydroxide is a neutralization reaction, where the acidic benzoic acid reacts with the basic sodium hydroxide to form a salt and water.
The balanced equation for this reaction can be represented as follows:
C6H5COOH + NaOH → C6H5COONa + H2O
This equation indicates that one molecule of benzoic acid reacts with one molecule of sodium hydroxide to produce one molecule of sodium benzoate (C6H5COONa) and one molecule of water (H2O).
To balance the equation, we have ensured that the number of atoms on both sides is equal. Here, we have one carbon (C) atom, seven hydrogen (H) atoms, two oxygen (O) atoms, one sodium (Na) atom, and one hydroxide (OH-) ion on both sides of the equation, making it a balanced equation.