How much heat energy is required to raise the temperature of 5Kilograms of a coal from 20 C to 220 C ?
Coal? Doesnt coal decompose before 220C>
1,314,718 j is the correct answer to this question, I just finished a test with that same qustion on it.
To calculate the amount of heat energy required to raise the temperature of a substance, we will use the formula:
Q = m * c * ΔT
Where:
Q = heat energy (in joules)
m = mass of the substance (in kilograms)
c = specific heat capacity of the substance (in joules per kilogram per degree Celsius)
ΔT = change in temperature (in degrees Celsius)
First, we need to determine if coal is the appropriate substance to use in this calculation. It is true that coal is a complex mixture of organic compounds and minerals, and its behavior at high temperatures can vary. Coal can indeed decompose at high temperatures. However, for the purpose of this calculation, let's assume that the specific heat capacity and the behavior of coal are relatively constant in the range of temperatures given (20°C to 220°C).
Now let's plug in the values into the formula:
m = 5 kilograms (given)
c = unknown (we need to determine the specific heat capacity of coal)
ΔT = (220°C - 20°C) = 200°C
To find the specific heat capacity of coal, we need to consult reliable sources such as scientific literature, textbooks, or experiments. Let's assume that the specific heat capacity of coal is 0.28 J/g°C (joules per gram per degree Celsius).
Specific heat capacity (c) needs to be in joules per kilogram per degree Celsius, so we need to convert it by dividing it by 1000:
c = 0.28 J/g°C ÷ 1000 = 0.00028 J/kg°C
Now, we can calculate the heat energy (Q):
Q = 5 kg * 0.00028 J/kg°C * 200°C = 0.28 J/g°C * 1000 g/kg * 200°C = 5,600 J
Therefore, the heat energy required to raise the temperature of 5 kilograms of coal from 20°C to 220°C is 5,600 joules.
If you got a different answer, it is possible that there was an error in the calculation or an incorrect value was used. It's always a good idea to double-check your work and ensure that the correct values and units are used in the calculation.