Can you help me find the roots of the polynominal of 5x2 - x....I believe it is 0 and 5...
I need help in finding the factorization of x2 - 15x + 56
and can u help me in finding the solutions of the equation x2 + 30x = 1000...
I came up with 20 and 50..but i think it is wrong....thank You
you have to type in the school subject for a expert to answer your question
Need more info for the first problem.x(5x-1) = ?
What numbers will give you a product of 56 and add to -15?
x(x+30) = 1000
Please only post your questions once. Repeating posts will not get a quicker response. In addition, it wastes our time looking over reposts that have already been answered in another post. Thank you.
Sure, I can help you with both the factorization of the polynomial and finding the solutions of the equation.
To find the factorization of a quadratic polynomial, use the quadratic formula or try factoring by grouping. In this case, let's try factoring by grouping for the polynomial x^2 - 15x + 56:
1. Find two numbers that multiply to give you the constant term (56) and add up to give you the coefficient of the middle term (-15).
The numbers that satisfy this condition are -7 and -8, as -7 * -8 = 56 and -7 + (-8) = -15.
2. Rewrite the middle term (-15x) by splitting it into two terms using the numbers found in step 1.
x^2 - 7x - 8x + 56
3. Group the terms and factor by grouping:
(x^2 - 7x) - (8x - 56)
x(x - 7) - 8(x - 7)
(x - 8)(x - 7)
Therefore, the factorization of x^2 - 15x + 56 is (x - 8)(x - 7).
Now, let's find the solutions of the equation x^2 + 30x = 1000:
1. Rewrite the equation in standard quadratic form (ax^2 + bx + c = 0):
x^2 + 30x - 1000 = 0
2. To solve this equation, you can use the quadratic formula, which states that for an equation of the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± sqrt(b^2 - 4ac)) / (2a)
For our equation, a = 1, b = 30, and c = -1000, substituting these values into the quadratic formula, we get:
x = (-30 ± sqrt(30^2 - 4*1*(-1000))) / (2*1)
Simplifying further:
x = (-30 ± sqrt(900 + 4000)) / 2
x = (-30 ± sqrt(4900)) / 2
x = (-30 ± 70) / 2
So, the solutions are:
x = (-30 + 70) / 2 = 40 / 2 = 20
x = (-30 - 70) / 2 = -100 / 2 = -50
Therefore, the solutions to the equation x^2 + 30x = 1000 are x = 20 and x = -50.
I hope this helps! Let me know if you have any further questions.