sample of methane gas at 250K and 1.5atm has a volume of 3.0L. the temp change is 350K and volume is increased to 6.0L. what is the new pressure?

Use (P1V1)/T1 = (P2V2)/T2

P=(3.0/6.0) x (250/350) 1.5

.53

To solve this problem, we can use the combined gas law equation:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

Where:
P1 and P2 are the initial and final pressures,
V1 and V2 are the initial and final volumes,
T1 and T2 are the initial and final temperatures.

Let's substitute the values given:

P1 = 1.5 atm
V1 = 3.0 L
T1 = 250 K
V2 = 6.0 L
T2 = 350 K

Now, let's plug these values into the equation and solve for P2:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

(1.5 atm * 3.0 L) / (250 K) = (P2 * 6.0 L) / (350 K)

4.5 atm L / 250 K = 6.0 L * P2 / 350 K

Simplifying further:

4.5 / 250 = P2 / 350

0.018 = P2 / 350

To find P2, multiply both sides by 350:

0.018 * 350 = P2

6.3 ≈ P2

Therefore, the new pressure (P2) is approximately 6.3 atm.