A beam of unknown charged particles passes at right angle to the direction of magnetic field of 9.0 10-2 T. If the speed of the particles is 3.0 104 m/s and force experienced by a particle is 8.64 10-16 N, how many electric charges are carried by one particle?
{Force} = F = {Charge}*{Velocity}*{Magnetic Field Strength} = Q*V*B
----> {Charge} = Q = F/(V*B)
----> {Charge} = (8.64e-16)/((3.0e+4)*(9.0e-2))
----> {Charge} = 3.2e-19 Coulombs
----> {# Electric Charges} = {Charge}/(1.6e-19)
----> {# Electric Charges} = (3.2e-19)/(1.6e-19)
----> {# Electric Charges Per Particle} = 2
correct thinking.
To find the number of electric charges carried by one particle, you can use the equation:
Charge = Force / (Velocity * Magnetic Field Strength)
Plug in the given values:
Force = 8.64e-16 N
Velocity = 3.0e4 m/s
Magnetic Field Strength = 9.0e-2 T
Calculate the charge:
Charge = (8.64e-16) / ((3.0e4) * (9.0e-2))
Charge = 3.2e-19 Coulombs
Since one elementary charge is 1.6e-19 Coulombs, you can convert the charge to the number of electric charges per particle:
Number of electric charges = Charge / (1.6e-19)
Calculate the number of electric charges:
Number of electric charges = (3.2e-19) / (1.6e-19)
Number of electric charges = 2
Therefore, one particle carries 2 electric charges.