Calculate the specific heat of a metallic element if 314 jouldes of heat energy are needed to raise the temperature of a 50g sample from 25 degrees Celcius to 50 degrees Celcius?
1. Note the correct spelling of celsius.
2.
q = mass x specific heat x delta T.
Substitute and solve for specific heat.
Does the density of air change when it is heated in a closed container?
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To calculate the specific heat of a metallic element, you need to use the formula:
Q = m * c * ΔT
Where:
Q is the heat energy (in joules)
m is the mass of the sample (in grams)
c is the specific heat of the material (in joules per gram-degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
In this case, you are given:
Q = 314 joules
m = 50 grams
ΔT = (50 degrees Celsius) - (25 degrees Celsius) = 25 degrees Celsius
Plug in the given values into the formula and solve for c:
314 joules = 50 grams * c * 25 degrees Celsius
Divide both sides of the equation by (50 grams * 25 degrees Celsius):
314 joules / (50 grams * 25 degrees Celsius) = c
Simplifying the equation:
0.125 joules per gram-degree Celsius = c
Therefore, the specific heat of the metallic element is 0.125 joules per gram-degree Celsius.