a=3,b=2,c=2

would this make a triangle? if so, how would i find the angles?

thanks for helping.

You would find the angles using the cosine law. When all three sides are given to a triangle, you can solve for each angle.

To determine whether the given sides (a, b, c) can form a triangle, you need to check if the sum of any two sides is greater than the third side. In this case, let's verify if this condition is met:

a + b > c
3 + 2 > 2
5 > 2 ✓

b + c > a
2 + 2 > 3
4 > 3 ✓

c + a > b
2 + 3 > 2
5 > 2 ✓

Since all three conditions are met, the given sides (a, b, c) can form a triangle.

To find the angles, you can use the cosine law. The cosine law states that, for any triangle with sides a, b, and c opposite angles A, B, and C, respectively:

c^2 = a^2 + b^2 - 2ab * cos(C)
a^2 = b^2 + c^2 - 2bc * cos(A)
b^2 = c^2 + a^2 - 2ca * cos(B)

In this case, you have the side lengths a = 3, b = 2, and c = 2. To find the angles, you can use these formulas and substitute the values:

For angle C:
c^2 = a^2 + b^2 - 2ab * cos(C)
2^2 = 3^2 + 2^2 - 2(3)(2) * cos(C)
4 = 9 + 4 - 12 * cos(C)
4 = 13 - 12 * cos(C)
12 * cos(C) = 13 - 4
12 * cos(C) = 9
cos(C) = 9/12
cos(C) = 3/4

To find angle C, you would take the arccosine of 3/4 (cos^-1(3/4)) using a calculator or computer software. The result is approximately 41.41 degrees.

Similarly, you can solve for angles A and B using the same approach. Note that you may need to rearrange the formulas to solve for the desired angle.

I hope this helps! Let me know if you have any further questions.