The mass of a single barium atom is 2.28E-22 grams. How many barium atoms would there be in 37.4 milligrams of barium
0.0374 g x (1 atom/2.28 x 10^022 g) = ??
To find the number of barium atoms in 37.4 milligrams of barium, you need to convert milligrams to grams and then use the molar mass of barium to calculate the number of atoms.
Here's how you can do it step by step:
Step 1: Convert milligrams to grams:
To convert milligrams to grams, divide the value by 1000.
37.4 milligrams ÷ 1000 = 0.0374 grams
Step 2: Determine the molar mass of Barium:
The molar mass of Barium (Ba) is 137.33 grams/mole. This means that one mole of Ba weighs 137.33 grams.
Step 3: Calculate the number of moles:
To find the number of moles, divide the mass (in grams) by the molar mass (grams/mole).
Number of moles = Mass of Barium (in grams) / Molar mass of Barium
Number of moles = 0.0374 grams / 137.33 grams/mole
Step 4: Calculate the number of atoms:
Avogadro's number states that there are 6.022 x 10^23 atoms in one mole of any substance.
Number of atoms = Number of moles x Avogadro's number
Number of atoms = (0.0374 grams / 137.33 grams/mole) x (6.022 x 10^23 atoms/mole)
Calculating this equation will give you the number of barium atoms in 37.4 milligrams of barium.