How do you solve this question:
The cost of 3 markers and 2 pencils is $1.80. The cost of 4 markers and 6 pencils is $2.90. What is the cost of each item?
If you put the cost of a marker as x, and the cost of a pencil is y, then
3x+2y=?
and if you do the same for the second part of the question, you will end up with two equations with two unknowns from which you should be able to solve for x and y.
let the cost of a marker be x
let the cost of a pencil by y
3x + 2y = 180
4x + 6y = 290
I would triple the first equation
9x + 6y = 540
then subtract the second from that to get
5x = 250
x=50
take it from there
thank you!
To solve this question, we can use a system of equations. Let's represent the cost of one marker as "m" and the cost of one pencil as "p".
Based on the information given, we can set up two equations:
Equation 1: 3m + 2p = 1.80
Equation 2: 4m + 6p = 2.90
To solve this system of equations, we can use the method of substitution.
First, solve Equation 1 for "m" in terms of "p":
3m = 1.80 - 2p
m = (1.80 - 2p) / 3
Now plug this expression for "m" into Equation 2:
4[(1.80 - 2p) / 3] + 6p = 2.90
Simplify the equation:
(7.20 - 8p) / 3 + 6p = 2.90
Multiply both sides of the equation by 3 to eliminate the fraction:
7.20 - 8p + 18p = 8.70
Combine like terms:
-8p + 18p = 8.70 - 7.20
10p = 1.50
Divide both sides by 10:
p = 0.15
Now substitute the value of "p" back into Equation 1 to find the cost of one marker:
3m + 2(0.15) = 1.80
3m + 0.30 = 1.80
Subtract 0.30 from both sides:
3m = 1.80 - 0.30
3m = 1.50
Divide both sides by 3:
m = 0.50
So, the cost of one marker is $0.50 and the cost of one pencil is $0.15.