Find the values of x and y for which:
[2y+5] [x-1]
[y - 2] = [ 3x ] is true.
a. (-1, -1)
b. (-2, -4)
c. (5, 1)
d. (-1, 4)
I got B...?
To find the values of x and y for which the given equation is true, we can set up a system of equations. Here's how:
Step 1: Set up the system of equations using the given equation:
2y + 5 = x - 1 (Equation 1)
y - 2 = 3x (Equation 2)
Step 2: Solve the system of equations to find the values of x and y. Let's solve it using the substitution method:
From Equation 2, we can express y in terms of x:
y = 3x + 2
Substitute this value of y into Equation 1:
2(3x + 2) + 5 = x - 1
Expand and simplify:
6x + 4 + 5 = x - 1
6x + 9 = x - 1
Combine like terms:
6x - x = -1 - 9
5x = -10
Divide both sides by 5:
x = -2
Substitute this value of x back into Equation 2 to find y:
y = 3(-2) + 2
y = -6 + 2
y = -4
Therefore, the values of x and y that satisfy the given equation are x = -2 and y = -4.
So, the correct answer is:
b. (-2, -4)
You are correct!