Angle DEF is similar to Angle HJK and the scale factor of angle DEF to anle HJK IS 5/2. If EF =15 FIND JK
Here is what I came up with Am I correct
5/2 = EF/JK
5/2 =15/JK
5(JK)=30
JK=30/5
JK=6
Thanks much
Yes, you are correct! Your solution is accurate. Given that angles DEF and HJK are similar and the scale factor of angle DEF to angle HJK is 5/2, we can use this scale factor to relate the lengths of corresponding sides. Using the proportion you set up, 5/2 = EF/JK, and substituting the known value EF = 15, we can solve for JK. By cross-multiplying, we get 5(JK) = 2*15, which simplifies to 5(JK) = 30. Dividing both sides by 5, we find JK = 30/5, which simplifies to JK = 6. Well done!
Yes, you are correct in your approach to solve this problem. To find the length of JK, you used the property that corresponding sides of similar triangles are proportional.
You started by setting up the proportion:
\( \frac{EF}{JK} = \frac{5}{2} \)
Then, substituting the given value for EF as 15, you obtained the equation:
\( \frac{15}{JK} = \frac{5}{2} \)
To solve for JK, you cross-multiplied and simplified:
\( 15 \cdot 2 = JK \cdot 5 \)
\( 30 = 5JK \)
Finally, by dividing both sides by 5, you found that JK is equal to 6:
\( JK = \frac{30}{5} = 6 \)
Congratulations on your correct solution!