What is the molarity of a solution that contains 125 g NaCl in 4.00 L solution?
a.8. 56 M
b.31.3 M
c. 2.14 M
d/ 0.535 M
i did it and i got d
good, excellent
To determine the molarity of a solution, you need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
To find the moles of solute, you first need to convert grams of NaCl to moles. The molar mass of NaCl is 58.44 g/mol.
moles of NaCl = mass of NaCl / molar mass of NaCl
moles of NaCl = 125 g / 58.44 g/mol
Next, you need to determine the volume of the solution in liters. In this case, the volume is given as 4.00 L.
Now, substitute the values into the formula:
Molarity (M) = moles of NaCl / volume of solution
Molarity (M) = (125 g / 58.44 g/mol) / 4.00 L
By performing the calculations, you will find that the molarity is approximately 2.14 M (option c).
For these molarity problems, just remember the definition.
Molarity = # mols/Liter of solution.
So convert grams NaCl to moles (# moles = g/molar mass) and divide by the number of liters. Voila!
is it b
I assume the molmass of NaCl is about 58
Molarity=mass/(molmass*literssolution)