write an equation in slope intercept form to represent the table of values.

x=2 3 5 6
y=-3 -4 -6 -7

please help me solve it, i find it complicating

Use the slope formula Y2-Y1/X2-X1 to find the slope and then insert that for m in the slope intercept for y = mx+b then plug in one of the sets of values for y and x to find b.

i can solve it for you if you want...

please do, it would be very helpful

(-4)-(-3)/(3)-(2)=-1

y=-1x+b

-3=-1(2)+b
-3=-2+b
-1=b

y=-x-1

is that good?

How to solve an equation in Slope intercept form, to represent the relationship of values given in each table

To write an equation in slope-intercept form, which is in the form y = mx + b, we need to find the slope (m) and y-intercept (b) values. Here's how we can do it step by step:

Step 1: Choose any two points from the given table of values. Let's choose the points (2, -3) and (5, -6).

Step 2: Calculate the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)

Using the coordinates (2, -3) and (5, -6):
m = (-6 - (-3)) / (5 - 2)
= (-6 + 3) / 3
= -3 / 3
= -1

Therefore, the slope (m) is -1.

Step 3: Now, we can substitute the slope (m) and the coordinates of any point (x, y) into the slope-intercept form equation (y = mx + b) to solve for the y-intercept (b).

Using the point (2, -3):
-3 = -1 * 2 + b
-3 = -2 + b
b = -3 + 2
b = -1

Therefore, the y-intercept (b) is -1.

Step 4: Now that we have both the slope (m = -1) and the y-intercept (b = -1), we can write the equation in slope-intercept form:
y = -1x - 1

Simplifying it, we get:
y = -x - 1

So, the equation in slope-intercept form that represents the given table of values is y = -x - 1.