Find the axis of symmetry.
y = -x^2+8x+2
4
To find the axis of symmetry for a quadratic equation in the form of y = ax^2 + bx + c, you can use the formula:
x = -b / (2a)
In your equation, y = -x^2 + 8x + 2, the coefficient of x^2 is -1, which we can denote as a, the coefficient of x is 8, which we can denote as b, and the constant term is 2, which we can denote as c.
Using the formula, we can substitute the values of a and b into the equation:
x = -8 / (2 * -1)
Simplifying further:
x = -8 / -2
x = 4
Therefore, the axis of symmetry for the equation y = -x^2 + 8x + 2 is x = 4.