A cannonball is fired horizontally from a 240 -high cliff toward a vertical building 540 away with an initial velocity of 90.0 .
When the ball will hit the building?
A) 7.00 s
B) 6.00 s
C) less than 6.00 s
D) more than 7.00 s
If it's fired horizontally, then all of the velocity component is horizontal. Thus s=v*t so
t=540/90
How far will the object fall during that time period though?
I'm supposing that all the units are compatible. There are none given so I really don't know what to make of the question?
I do not know
To determine when the cannonball will hit the building, we can use the time it takes for the cannonball to travel horizontally across the 540m distance.
Since the initial velocity is purely horizontal, we can use the formula: distance = velocity × time.
We know the distance is 540m and the velocity is 90.0m/s, so we can rearrange the formula and solve for time: time = distance / velocity.
Substituting the values, we have: time = 540m / 90.0m/s = 6.00s.
Therefore, the cannonball will hit the building after 6.00 seconds.
So the correct answer is B) 6.00 s.