The exterior angle of a regular polygon is the angle formed by an extended side and the adjacent side.
a)what is the measure of each interior angel of a regular pentagon.
(There is apicture on the page and each side measures 21mm)
Help please.
As I said in response to a previous question, the sum of the exterior angles is 360 degrees. If all N angles are the same (as in the case of a regular polygon), divided 360 by N for the exterior angle of each.
To find the measure of each interior angle of a regular polygon, you can use the formula:
Interior angle = (n-2) * 180 / n,
where 'n' represents the number of sides of the polygon.
In this case, you mentioned a regular pentagon, which has 5 sides. So, plugging in 'n=5' into the formula, we can calculate the measure of each interior angle as follows:
Interior angle = (5-2) * 180 / 5
= 3 * 180 / 5
= 540 / 5
= 108 degrees
Therefore, each interior angle of a regular pentagon measures 108 degrees.
However, the given information about the lengths of the sides (21mm) is not relevant to finding the measure of the interior angles. It seems like an extraneous piece of information.