ƒ(x) = 8x2 − 4x − 5

For the given function Æ’, match each domain value to its corresponding range value?

1,0,1/2,2 in place of x

To find the corresponding range values for the given domain values in the function Æ’(x) = 8x^2 - 4x - 5, we need to substitute each domain value into the function and calculate the corresponding range value.

Let's start by substituting the first domain value, x = 1, into the function Æ’(x):
Æ’(1) = 8(1)^2 - 4(1) - 5
Æ’(1) = 8 - 4 - 5
Æ’(1) = -1

So, when x = 1, the corresponding range value is -1.

Next, substitute the second domain value, x = 0, into the function Æ’(x):
Æ’(0) = 8(0)^2 - 4(0) - 5
Æ’(0) = 0 - 0 - 5
Æ’(0) = -5

Therefore, when x = 0, the corresponding range value is -5.

Now, let's substitute the third domain value, x = 1/2, into the function Æ’(x):
Æ’(1/2) = 8(1/2)^2 - 4(1/2) - 5
Æ’(1/2) = 8(1/4) - 4/2 - 5
Æ’(1/2) = 2 - 2 - 5
Æ’(1/2) = -5

Hence, when x = 1/2, the corresponding range value is also -5.

Finally, substitute the fourth domain value, x = 2, into the function Æ’(x):
Æ’(2) = 8(2)^2 - 4(2) - 5
Æ’(2) = 8(4) - 8 - 5
Æ’(2) = 32 - 8 - 5
Æ’(2) = 19

So, when x = 2, the corresponding range value is 19.

Therefore, the matching domain and range values are:
(1, -1)
(0, -5)
(1/2, -5)
(2, 19)