Respond to this Question
Similar Questions

Algebra2
Find the polynomials roots to each of the following problems: #1) x^2+3x+1 #2) x^2+4x+3=0 #3) 2x^2+4x5 #3 is not an equation. Dod you omit "= 0" at the end? #2 can be factored into (x+1)(x+3) = 0, so the roots are x=1 and 3.
asked by Haylee on May 13, 2007 
Alegbra 2
Use the rational root theorem to list all possible rational roots for the equation. X^3+2x9=0. Use the rational root theorem to list all possible rational roots for the equation. 3X^3+9x6=0. A polynomial function P(x) with
asked by Chelsey on January 26, 2018 
Algebra
The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq. I think the obvious root would be one but the second roots i just
asked by Ricky on October 20, 2011 
maths
Show that the equation (1) divided by (x+1)  (x)divided by (x2)=0 has no real roots Well, to begin, start with 1/(x+1x). The x's cancel out because they are opposite signs, so now you have 1/1, or just 1. Then, you are dividing
asked by rochelle on January 28, 2007 
Maths
Write down the equation whose roots are: i) two more than ii) the square of iii) three times as much as the roots of the equation 4x^2x+2=0
asked by Claire on November 26, 2007 
Precalculus
"Show that x^6  7x^3  8 = 0 has a quadratic form. Then find the two real roots and the four imaginary roots of this equation." I used synthetic division to get the real roots 2 and 1, but I can't figure out how to get the
asked by Emily on September 20, 2009 
Adv algebra
The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq.
asked by Ricky on October 22, 2011 
Math
The equation x^2+px+q=0, q cannot be equal to 0, has two unequal roots such that the squares of the roots are the same as the two roots. Calculate the product pq.
asked by Ricky C. on October 20, 2011 
college algebra
Radical and Rational Exponent find roots square roots of 12a^3/25=6a^3 3square roots 18/6=1 this is my answer am I right. check this for me it find the roots of the problem
asked by JohnJ on May 25, 2010 
algebra
1)Solve by factoring:5x^2=419x answer=4,1/5 2)Which quadratic equation has roots 7 and 2/3? answer=A A.2x^211x21=0 B.3x^219x14=0 C.3x^2+23x+14=0 D.2x^2+11x21=0 3)To solve 4x^228x+49=25 by using the square root
asked by Marissa on August 14, 2007