Calculate the equilibrium concentration of each compound if 0.340 moles of HI are placed in a 5.90 liter container at 520°C. Kc = 0.170 for the reaction at this temperature.
soo i tried doing this by setting up an ICE table
and finding what x equaled buuuut it didn't work..
please help! thanks
The ICE table should work. Post your work and I'll find your error.
sorry it was for this problem
Calculate the equilibrium concentration of each compound if 2.10 moles of CO2 and 3.70 moles of H2 are placed in a 2.90 liter container at 300°C. Kc = 1.90 for the reaction at this temperature.
okay so i did
CO2(g) + H2(g) = CO(g) + H2O(g)
.724-x..1.276-x......+x......+x
x^2/(.724-x)(1.276-x) =1.9
and i have
Quad form:
A=.9
B=-3.8
C=1.75522
Answer: 3.694=x
I get the same answer and the coefficients are the same as yours for one root but 3.69 cant be correct because you had only 0.724 initially. For the other root I calculated 0.528 but I didn't check my figures. That should be the answer to the problem. Check me out on that.
To solve this problem, you need to set up an ICE table and use the given equilibrium constant (Kc) to determine the equilibrium concentrations of the compounds.
First, write the balanced equation for the reaction:
HI ⇌ H2 + I2
Now, set up the ICE table:
HI ⇌ H2 + I2
Initial: 0.340 0 0
Change: -x +x +x
Equilibrium: 0.340 - x x x
The equilibrium concentrations are given by the expressions 0.340 - x for HI, x for H2, and x for I2.
Since Kc = 0.170 is given, you can use this information to set up an equation:
Kc = [H2] * [I2] / [HI]
Substituting the equilibrium concentrations into the equation:
0.170 = (x) * (x) / (0.340 - x)
Now, solve for x by rearranging the equation:
0.170(0.340 - x) = x^2
0.0578 - 0.170x = x^2
Rearrange the equation to bring everything to one side:
x^2 + 0.170x - 0.0578 = 0
Now you can solve this quadratic equation using the quadratic formula or by factoring. Once you find the value of x, you can substitute it back into the equilibrium concentrations expressions to calculate the equilibrium concentrations of each compound.
Note: Since this is a quadratic equation, there may be two values of x. However, you should only consider the positive value of x, as negative concentrations are not physically meaningful.
I hope this helps you solve the problem! Let me know if you need further assistance.