Find the GCF of each product.
(6y^2-3y)(y+7)
I think it is 3y. I'm not sure maybe there is no GCF in this problem. Any help would be appreciated.
yea your right its 3y
To find the greatest common factor (GCF) of the given product (6y^2 - 3y)(y + 7), you can use the distributive property to multiply the terms together.
(6y^2 - 3y)(y + 7) = 6y^3 + 42y^2 - 3y^2 - 21y
Now, you can combine the like terms to simplify the expression:
= 6y^3 + 39y^2 - 21y
To find the GCF, you need to determine the highest exponent that is common in all the terms. In this case, the term containing the highest exponent of y is y^2.
Therefore, the GCF in this product is y^2.
So, it appears that there is no common factor which can be extracted from the terms (6y^2 - 3y) and (y + 7). Hence, the GCF of the given product is y^2 if we consider only the exponent. However, if you are also considering the coefficient, then there is no GCF in this case.
In conclusion, the GCF of the product (6y^2 - 3y)(y + 7) is y^2.