algebra

Janet invested \$23,000, part at 6% and part at 17%. If the total interest at the end of the year is \$2,260, how much did she invest at 6%?

Let x be the amount invested at 6%
Then 23,000 - x is invested at 17%.

0.06 x + 0.17 (23,000 - x) = 2260.

That equation can be solved fo x

1. 👍 0
2. 👎 0
3. 👁 174
1. 15,000

1. 👍 0
2. 👎 0
posted by Mac

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