A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 3.55 m and mass 10.31 Kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.406 rad/s2.

Should I set the given angular acceleration equal to Torque/ (1/3 * m* r2) and solve for Torque?


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