An electron has a total energy of 2.8 MeV. What is its momentum?

In c = 1 units:

E^2 - p^2 = m^2 ------>

p = sqrt[E^2 - m^2] =

sqrt[2.8^2 - 0.511^2] MeV =

2.753 MeV

Put c back by dividing by c

p = 2.753 MeV/c = 1.47*10^(-21) kg m/s

To find the momentum of an electron with a given total energy, we can use the equation that relates energy and momentum for a particle moving at approximately the speed of light:

E^2 = (pc)^2 + (mc^2)^2

Where:
E is the total energy of the electron
p is the momentum of the electron
c is the speed of light in a vacuum
m is the rest mass of the electron

In this case, the electron has a total energy of 2.8 MeV. Since the mass of an electron is approximately 9.11 x 10^-31 kg and the speed of light is approximately 3 x 10^8 m/s, we can substitute these values into the equation:

(2.8 MeV)^2 = (p * c)^2 + (9.11 x 10^-31 kg * c^2)^2

Simplifying the equation, we have:

(2.8 x 10^6 eV)^2 = (p * 3 x 10^8 m/s)^2 + (9.11 x 10^-31 kg * (3 x 10^8 m/s)^2)^2

(2.8 x 10^6 eV)^2 - (9.11 x 10^-31 kg * (3 x 10^8 m/s)^2)^2 = (p * 3 x 10^8 m/s)^2

Taking the square root of both sides:

p * 3 x 10^8 m/s = sqrt[(2.8 x 10^6 eV)^2 - (9.11 x 10^-31 kg * (3 x 10^8 m/s)^2)^2]

Finally, solving for p:

p = sqrt[(2.8 x 10^6 eV)^2 - (9.11 x 10^-31 kg * (3 x 10^8 m/s)^2)^2] / (3 x 10^8 m/s)

Calculating the expression gives us the momentum of the electron.

To find the momentum of an electron, we can use the equation:

Momentum (p) = √(2mE),

where m is the mass of the electron and E is its total energy.

The mass of an electron (m) is approximately 9.11 x 10^-31 kilograms.

Given that the total energy (E) is 2.8 MeV, we need to convert it to joules since the SI unit of energy is the joule.

1 MeV is equal to 1.6 x 10^-13 joules.

Converting the total energy to joules, we get:

2.8 MeV x (1.6 x 10^-13 J/1 MeV) = 4.48 x 10^-13 J.

Now, we can substitute the values into the equation:

Momentum (p) = √(2 x (9.11 x 10^-31 kg) x (4.48 x 10^-13 J)),

Momentum (p) = √(8.09 x 10^-43 kg m^2/s^2).

Finally, we can calculate the momentum:

p ≈ 2.84 x 10^-22 kg m/s.

Therefore, the momentum of the electron is approximately 2.84 x 10^-22 kg m/s.