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write (27a^3)^(2/3) in simplest form. solve log(6x+11)=2 please and thanks I am not going to give you the answers. I will be happy to critique your work. In the first, remember that (a^b)^c= a^bc I am not looking for the
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write (27a^3)^(2/3) in simplest form. solve log(6x+11)=2 please and thanks I need to see your work on the first. On the second, take the antilog of each side what is the antilog? I'm not quite sure what to do for the first, but
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