Two cards are drawn wtihout replacement from a shuffled deck of 52 cards. What is the probability that the second card is each card?
a) an ace
P(BlA)= P(A&B)/P(A)
P(BlA) = (1/208)/(1/52)
=1/4 :S
did I use the correct formula? The answer didn't come out correct
what and the world is this what type of math are you taking?
it's probability.
To find the probability that the second card drawn is an ace, given that the first card drawn is an ace, we can use the formula:
P(B|A) = P(A ∩ B) / P(A)
In this case, A represents the event of drawing an ace for the first card, and B represents the event of drawing an ace for the second card.
There are 4 aces in a deck of 52 cards, so for the first card, the probability of drawing an ace is 4/52. Since the card is not being replaced, there are now only 3 aces left in a deck of 51 cards. So for the second card, the probability of drawing an ace is 3/51.
Plugging these values into the formula:
P(B|A) = (4/52) * (3/51) = 1/221
Therefore, the correct probability that the second card is an ace, given that the first card is an ace, is 1/221.