A painter needs to cover a triangular region 61 meters by 66 meters by 72 meters. A can of paint covers 70 square meters. How many cans will be needed?
would it be 1878.58 divided by 70m^2 =
4900/1878.58= 2.6 so 3 cans
This question was asked and answered about two weeks ago. Were you the person who posted the question? Did you see the answer?
There is a formula for the area of a triangle in terms of the lengths of three sides, which I provided in my previous answer. Use that formula.
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Divide the area by 70 m^2 per can for the number of cans.
Yes. That is the correct area and number of cans
To find the number of cans of paint needed, we need to calculate the total area of the triangular region and then divide it by the area covered by one can of paint.
To find the area of a triangle, we can use Heron's formula, which states that the area of a triangle with side lengths a, b, and c is given by:
area = √(s(s-a)(s-b)(s-c))
where s is the semi-perimeter of the triangle, which is half the sum of its sides:
s = (a + b + c) / 2
Let's calculate the semi-perimeter and the area of the triangle:
s = (61 + 66 + 72) / 2 = 199 / 2 = 99.5
area = √(99.5(99.5-61)(99.5-66)(99.5-72))
= √(99.5 * 38.5 * 33.5 * 27.5)
= √(99117006.25)
≈ 9955.85 square meters
Now that we know the total area of the triangular region is approximately 9955.85 square meters, we can divide it by the area covered by one can of paint:
cans = area / area per can
= 9955.85 / 70
≈ 142.23
Therefore, the painter will need approximately 142 cans of paint to cover the triangular region.