Factor : (4x^2-7x+3) - (3x^2-5x)
(4x^2-7x+3) - (3x^2-5x)
= (x-1)(4x-3)-x(3x+5)
Check my work.
My guess as to what the problem is needing:
(4x^2 - 7x + 3) - (3x^2 - 5x)
remove parentheses then combine like terms
4x^2 - 7x + 3 - 3x^2 + 5x
4x^2 - 3x^2 - 7x + 5x + 3
x^2 - 2x + 3
Then factor x^2 - 2x + 3
To factor the expression (4x^2 - 7x + 3) - (3x^2 - 5x), we will first distribute the negative sign to the terms inside the parentheses.
(4x^2 - 7x + 3) - (3x^2 - 5x) becomes:
4x^2 - 7x + 3 - 3x^2 + 5x
Next, we combine the like terms:
(4x^2 - 3x^2) + (-7x + 5x) + 3
Simplifying further:
x^2 - 2x + 3
We cannot factor this quadratic expression any further using integers or rational numbers. Therefore, the factored form of the expression (4x^2 - 7x + 3) - (3x^2 - 5x) is x^2 - 2x + 3.