r^2+8r=48

First bring the 48 to the other side of the equation

r^2+8r-48=0

Now you can use the quadratic formula.

x=-b+-sqrt(b^2-(4ac))
¯¯¯¯¯¯¯2a¯¯¯¯¯¯¯¯¯

So...
a=1
b=8
c=-48

Now just plug the numbers into the quadratic equation and get your two answers.

The answers are: x=-12 and x=4

Feel free to ask if you need any more help. :-)

To solve the equation r^2 + 8r = 48, follow these steps:

1. Move the 48 to the other side of the equation: r^2 + 8r - 48 = 0
2. Now you have a quadratic equation in the form of ax^2 + bx + c = 0, where a = 1, b = 8, and c = -48.
3. Use the quadratic formula to find the solutions for r:

r = (-b ± sqrt(b^2 - 4ac)) / (2a)

Plug in the values: r = (-(8) ± sqrt((8)^2 - 4(1)(-48))) / (2(1))

4. Calculate the values inside the square root: sqrt(64 + 192) = sqrt(256) = 16

So, the equation becomes r = (-8 ± 16) / 2

5. Simplify: r1 = (-8 + 16) / 2 = 8 / 2 = 4, and r2 = (-8 - 16) / 2 = -24 / 2 = -12

Therefore, the solutions to the equation r^2 + 8r = 48 are r = 4 and r = -12.