Add.
4m^2yp + 6/m^y
Even though you have posted this more than once you have not been getting an answer because your question is unclear
I assume you mean 4m^(2yp) + 6/m^y
common denominator would be m^y
so (4m^(3yp) + 6)/m^y would be the sum
yes that's what I mean
To add the given expressions, 4m^2yp and 6/m^y, we need to have a common denominator for both terms.
First, let's rewrite the expressions so that they have the same denominator. To do this, we'll multiply the first expression, 4m^2yp, by m^y/m^y and the second expression, 6/m^y, by m^2/m^2:
= (4m^2yp * m^y) / (m^y) + (6/m^y * m^2) / (m^2)
Simplifying this, we get:
= (4m^(2+y) * y * p) / (m^y) + (6 * m^2) / (m^2 * m^y)
Next, we can combine the two terms since they now have a common denominator:
= (4m^(2+y) * y * p + 6 * m^2) / (m^2 * m^y)
Finally, we simplify the expression if possible. Since the numerator and denominator do not share any common factors, we cannot simplify it further.
Therefore, the final sum is:
= (4m^(2+y) * y * p + 6 * m^2) / (m^2 * m^y)