this maths problem is wrecking my head....

1.find the points of interesction of the line L and the circle k in the following

L:x-2y=0
K:X Squared + y squared=25

I would solve both equations for y, and then you'll have a system with two equations and two variables:

y = x/2
y = (plusorminus) sqrt(25 - x^2)

Solve the system and you'll have your points of intersection.

Use the substitution method to solve these equations. This is not a linear system because of the exponents in K.
We hve
L: x-2y=0
K: x^2+y^2=25
L is a line with slope 1/2 that goes through the origin.
K is a circle of radius 5 centered at the origin.
From L we have x=2y. Using this for x in K we have
(2y)^2+y^2=25 so 4y^2+y^2=5y^2=25 or,
y=+/-sqrt(5)
Use those values of y in either L or K to solve for the corresponding x values.
Be sure to check the answers by substituting in L and K.

I need help with this problem:

3y=15x-12

Please give me the answer ASAP. ;)

I need help with this problem:

3y=15x-12

Please give me the answer ASAP. ;)

I need help with this problem:

3y=15x-12

Please give me the answer ASAP. ;)

I need help with this problem:

3y=15x-12

Please give me the answer ASAP. ;)

i don't understand the equation?

It seems like you need help solving the equation:

3y = 15x - 12

To solve this equation for y, you'll want to perform the following steps:

Step 1: Divide both sides of the equation by 3 so that you can isolate the y variable:

y = 5x - 4

Now we have the equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope (m) is 5 and the y-intercept (b) is -4. This means that the graph of this equation is a line that goes through the point (0, -4) on the y-axis and has a slope of 5.

The equation 3y = 15x - 12 represents a linear relationship between y and x. To solve for the values of y and x, we can use the following steps:

Step 1: Divide both sides of the equation by 3 to isolate y:
y = (15x - 12)/3

Step 2: Simplify the equation:
y = 5x - 4

This equation represents a straight line with a slope of 5 and a y-intercept of -4.

If you have specific values of x or y, you can substitute them into the equation to find the corresponding values. For example, if x = 2, we can find the value of y:
y = 5(2) - 4
y = 10 - 4
y = 6

So for x = 2, y = 6.

To solve the equation 3y = 15x - 12, you can follow these steps:

Step 1: Re-arrange the equation to isolate the variable y:
Divide both sides of the equation by 3:
y = (15x - 12) / 3

Step 2: Simplify the right side of the equation:
Divide 15x by 3:
y = 5x - 4

The simplified equation is y = 5x - 4.

Now, I cannot give you a specific answer without any additional information or constraints. However, this equation represents a line in the slope-intercept form (y = mx + b), where the coefficient of x (m) is 5 and the y-intercept (b) is -4.