Can the remainder in division ever be equal to the divisor? please explain?
No, because that would mean that the divisor (or denominator) DID divide evenly into the dividend (or numerator) and thus there would be no remainder (same/same=1, no remainder)
In division, the remainder is always less than the divisor. The remainder represents what is left over after dividing the dividend (the number being divided) by the divisor (the number dividing the dividend). It indicates how many units are left over that cannot be divided evenly.
Here's an example to help illustrate this concept:
Let's say we have the division problem: 10 ÷ 3.
When we divide 10 by 3, we get a quotient of 3 and a remainder of 1. So, the division statement becomes 10 = 3 × 3 + 1.
In this example, the divisor is 3, and the remainder is 1. The remainder of 1 is less than the divisor of 3.
Now, let's consider the scenario where the remainder is equal to the divisor. For instance, if we divide 10 by 5.
When we divide 10 by 5, we get a quotient of 2 and a remainder of 0. The division statement becomes 10 = 5 × 2 + 0.
In this case, the remaining 0 indicates that there is nothing left over after dividing 10 evenly by 5. Therefore, the remainder is equal to the divisor.
So, to answer your question, in most cases, the remainder in division cannot be equal to the divisor. However, there are instances where the remainder can be zero, which makes it equal to the divisor.