I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?
The problem is 3y = 2x + 12
My Work:
0=2x+ 12
--------
2 2
x=6
You cannot solve this equation. It has 2 unknowns.
I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?
The problem is 3y = 2x + 12
My Work:
0=2x+ 12 How and/or why did you eliminate y from the equation.
--------
2 2
x=6
A ssuming you are seeking integer answers.
1--3y - 2x = 12
2--Dividing through by 2 yields y + y/2 - x = 6
3--y/2 must be an integer k mking y = 2k
4--Substituting back into (1)0 yields 6k - 2x = 12 making x = 3k - 6
5--CLearly, without any other conditions imposed by the problem statement, there are an infinite number of answers.
6--k...0...1...2...3...4...5...6..
...x..-6..-3...0...3...6...9..12..
...y...0...2...4...6...8..10..12..
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Homework Help Forum: Math
Current Questions | Post a New Question | Answer this Question | Further Reading
Posted by tchrwill on Monday, May 28, 2007 at 1:22pm in response to Math.
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I can't seem to do this problem. And my grade is riding on it. Can someone please help? I don't know how to solve it. Can someone help me by telling me what I'm doing wrong?
The problem is 3y = 2x + 12
My Work:
0=2x+ 12 How and/or why did you eliminate y from the equation.
--------
2 2
x=6
A ssuming you are seeking integer answers.
1--3y - 2x = 12
2--Dividing through by 2 yields y + y/2 - x = 6
3--y/2 must be an integer k making y = 2k
4--Substituting back into (1) yields 6k - 2x = 12 making x = 3k - 6
5--Clearly, without any other conditions imposed by the problem statement, there are an infinite number of answers.
6--k...0...1...2...3...4...5...6..etc.
...x..-6..-3...0...3...6...9..12..etc.
...y...0...2...4...6...8..10..12..etc.
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http://www.jiskha.com/display.cgi?id=1180111741
oh this is easy just...wait i have my own homework to do and i don't even know you
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In order to solve the equation 3y = 2x + 12, you need to have the same number of equations as the number of unknowns. In this case, you have one equation (3y = 2x + 12) and two unknowns (x and y). Therefore, you cannot solve this equation to find specific values for x and y.
In your work, it seems like you attempted to eliminate y from the equation by setting 3y equal to 0. However, this is not a valid step because it changes the original equation and does not lead to a solution for x or y.
To solve a system of equations with two unknowns, you would need another equation that relates x and y in some way. Without that additional equation, the system is underdetermined, meaning that there are infinitely many possible solutions.
In this case, you can express the equation in terms of one variable. By rearranging the equation, you can solve for y in terms of x or for x in terms of y. This will give you the relationship between the variables, but not specific values for x and y.