1) (6z-u)(6z+7u)
how do I Find the product for this?
I have 36z^2+36zu-7u^2 is that correct?
2) Also how do i complete the ordered given pairs for the equation x-3=0
Y is 4, 1, -3 what is x?
The first 1 is correct
For the second problem, You should make an x and y chart I THINK.
Thanks. What about find the slope, if it exists, of the line containing the given pair points
(-17,-3) and (-20,-9)
The slope M=
is this 2x+31 or 2x or just 2?
The formula to find that is
y2-y1/x2-x1
(-9 + 3)/(-20 + 7 )
-6/-13
6/13 << that is the slope
Okay, One last question. Perform the indicated operations
(9x^2-7x-66)(+8x^2+9x)
is this answer 17x^2+2x-66
8x^2(9x^2 - 7x - 66) + 9x(9x^2 - 7x - 66)
72x^4 + 25x^3 - 591^x2 - 594x
I could be wrong on this one
To find the product of (6z-u)(6z+7u), you can use the distributive property. Multiply each term in the first parentheses by each term in the second parentheses and then combine like terms, if any.
Here's the step-by-step solution:
1. Multiply the terms: 6z * 6z = 36z^2, 6z * 7u = 42zu, -u * 6z = -6uz, and -u * 7u = -7u^2.
2. Combine like terms: 36z^2 + 42zu - 6uz - 7u^2.
3. Simplify further if possible: 36z^2 + 36zu - 7u^2.
Therefore, your answer is 36z^2 + 36zu - 7u^2.
For the second question, to complete the ordered pairs for the equation x-3=0, you need to substitute the given values of y and solve for x.
Given y values: 4, 1, -3.
For y = 4:
1. Substitute y = 4 into the equation: x - 3 = 0.
2. Solve for x: x = 3 + 4, x = 7.
For y = 1:
1. Substitute y = 1 into the equation: x - 3 = 0.
2. Solve for x: x = 3 + 1, x = 4.
For y = -3:
1. Substitute y = -3 into the equation: x - 3 = 0.
2. Solve for x: x = 3 + (-3), x = 0.
Therefore, the corresponding x values for the given y values of 4, 1, and -3 are 7, 4, and 0 respectively.