3 h20 + N2 yields 2 NH3
how many moles of ammonia NH3 would be produced by reacting 6.00 moles of hydrogen H2 with an adequate amount of nitrogen N2
I suppose zero. You have no H2 reacting in the equation.
To determine the number of moles of ammonia (NH3) produced, we can use the given balanced chemical equation:
3 H2 + N2 --> 2 NH3
Looking at the coefficients of the reactant (H2) and product (NH3), we can see that the ratio of H2 to NH3 is 3:2. This means that for every 3 moles of H2, we will produce 2 moles of NH3.
Given that we have 6.00 moles of H2, we can use this ratio to calculate the moles of NH3 produced.
Moles of NH3 = (moles of H2 * moles of NH3) / moles of H2
Moles of NH3 = (6.00 mol H2 * 2 mol NH3) / 3 mol H2
Moles of NH3 = (12.00 mol NH3) / 3
Moles of NH3 = 4.00 mol NH3
Therefore, 6.00 moles of hydrogen (H2) would produce 4.00 moles of ammonia (NH3).