Solve the system by addition or substitution.
16x-4y=20
y=4x-4
I ask for help with this and forgot to add the problem. can anyone help me understand how to do this?
16x-4y=20
-4x+y=-4
___________
16x-4y=20
(4)(-4x+y=-4)
______________
16x-4y=20
-16x+4y=-16
______________
0=4
answer: empty set
16x - 4(4x-4) = 20
16x - 16x - 16 = 20
-16 = 20
It doesn't work. Anonymous is right. Empty Set.
76-78
To solve this system of equations by addition or substitution, we need to find a way to eliminate one variable so that we can solve for the other.
One method is to solve for y in one equation and substitute it into the other equation. Let's start with the second equation: y = 4x - 4.
Now, we can substitute this value of y into the first equation: 16x - 4y = 20. Substituting y as 4x - 4, we get:
16x - 4(4x-4) = 20
Simplifying this, we have:
16x - 16x + 16 = 20
-16 = 20
As you can see, this equation is not possible, as -16 is not equal to 20. Therefore, there is no solution to this system of equations. This can be represented as an empty set.
So, the answer is the empty set, indicating that there are no values of x and y that will satisfy both equations simultaneously.