A turnbuckle is needed to apply an 8kN force on a cable. If the efficiency of the turnbuckle is 40% and the force applied is 159.155N with a lever of 20cm in length.
a)Find Mechanical Advantage:
M.A.=Load/Effort
M.A.=8000/159.155
M.A.=50.265 (ans.)
b)Find the velocity ratio:
Efficiency=M.A./V.R.
V.R.=M.A./eff.
V.R.=50.265/0.4
V.R.=125.66 (ans.)
c)Find the mean pitch of thread:
V.R.=distance moved by effort/dist. moved by load
V.R.=2piL/2*pitch of thread
2*pitch of thread=2pi*200mm/125.66
Pitch of thread=10/2
Pitch of thread=5mm (ans.)
Is this correct?